js格式化时间间隔
需求
js计算时间间隔要求如下：
小于1分钟：刚刚 60
小于1小时：几分钟前 60*60
小于1天：几小时前 60*60*24
小于1周：几天前 60*60*24*7
小于1月：几周前 60*60*24*30
小于1年：几个月前 60*60*24*365
大于1年：几年前 60*60*24*365
具体实现
formatTimeFromNowZh-中文方法
formatTimeFromNowEn-英文方法
//1.中文方法
function formatTimeFromNowZh(time) {
// if (("" + time).length === 10) {
// time = parseInt(time) * 1000;
// } else {
// time = +time;
// }
const d = new Date(time);
const now = Date.now();
const diff = (now - d) / 1000;
// console.log('formatTimeFromNowZh time', time,'diff',diff)
if(diff < 0){//未来时间
return time
}
if (diff < 60) {
return "刚刚";
} else if (diff < 3600) {
return Math.floor(diff / 60) + "分钟前";
} else if (diff < 3600 * 24) {
return Math.floor(diff / 3600) + "小时前";
} else if (diff < 3600 * 24 * 7) {
return Math.floor(diff / (3600 * 24))+"天前";
}else if (diff < 3600 * 24 * 30) {
return Math.floor(diff / (3600 * 24 * 7))+"周前";
}else if (diff < 3600 * 24 * 365) {
let m = Math.floor(diff / (3600 * 24 * 30))
m = m==12?11:m
return m+"月前";
}else if (diff >= 3600 * 24 * 365) {
return Math.floor(diff / (3600 * 24 * 365))+"年前";
}else{
return time
}
}
//2.英文方法
function formatTimeFromNowEn(time) {
// if (("" + time).length === 10) {
// time = parseInt(time) * 1000;
// } else {
// time = +time;
// }
const d = new Date(time);
const now = Date.now();
const diff = (now - d) / 1000;
if(diff < 0){//未来时间
return time
}
if (diff < 60) {
return "Just now";
} else if (diff < 3600) {
let suffix = Math.floor(diff / 60) > 1?"minutes ago":"minute ago"
return Math.floor(diff / 60) +" "+suffix;
} else if (diff < 3600 * 24) {
let suffix = Math.floor(diff / 3600) > 1?"hours ago":"hour ago"
return Math.floor(diff / 3600)+" " + suffix;
} else if (diff < 3600 * 24 * 7) {
let suffix = Math.floor(diff / (3600 * 24)) > 1?"days ago":"day ago"
return Math.floor(diff / (3600 * 24))+" "+suffix;
}else if (diff < 3600 * 24 * 30) {
let suffix =Math.floor(diff / (3600 * 24 * 7)) > 1?"weeks ago":"week ago"
return Math.floor(diff / (3600 * 24 * 7))+" "+suffix;
}else if (diff < 3600 * 24 * 365) {
let m = Math.floor(diff / (3600 * 24 * 30))
m = m==12?11:m
let suffix = m > 1?"months ago":"month ago"
return m+" "+suffix;
}else if (diff >= 3600 * 24 * 365) {
let suffix = Math.floor(diff / (3600 * 24 * 30)) > 1?"years ago":"year ago"
return Math.floor(diff / (3600 * 24 * 365))+" "+suffix;
}else{
return time
}
}
版权声明
本文为 程序员青阳 原创文章，遵循 CC BY-NC-SA 4.0 版权协议，转载请附上原文链接及本声明。